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📅 March 10, 2026 👤 scraface

Mar 10, 2026

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\[ T(x) = 0.02x + 0.5\sqrt{x} + 14 \]
We compute \(T(150)\) and \(T(250)\), then find the difference to esti...
First, compute \(T(150)\):
\[ \sqrt{150} \approx 12.247 \]
T(150) = 0.02(150) + 0.5(12.247) + 14 = 3 + 6.1235 + 14 = 23.1235
Next, compute \(T(250)\):
\[ \sqrt{250} \approx 15.811 \]
T(250) = 0.02(250) + 0.5(15.811) + 14 = 5 + 7.9055 + 14 = 26.9055
The temperature increase is:
\[ \Delta T = T(250) - T(150) \approx 26.9055 - 23.1235 = 3.782 \]

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