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\[ e^-0.4 = 0.4 \] - Ready Digital AB

📅 March 10, 2026 👤 scraface

Mar 10, 2026

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c = \sqrt{8^2 + 15^2} = \sqrt{64 + 225} = \sqrt{289} = 17 \text{ cm}
A = \frac{1}{2} \times 8 \times 15 = 60 \text{ square cm}
s = \frac{8 + 15 + 17}{2} = 20 \text{ cm}
r = \frac{A}{s} = \frac{60}{20} = 3 \text{ cm}
Thus, the radius of the inscribed circle is \(\boxed{3}\) cm.**Questio...
To solve \(\tan 45^\circ + \tan 30^\circ\), we first find the values o...
We know:
\tan 45^\circ = 1
For \(\tan 30^\circ\), we use the identity for the tangent of 30 degre...
\tan 30^\circ = \frac{1}{\sqrt{3}}

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