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Home » \[ h = racv^2 \sin^2 heta2g \] - Ready Digital AB

\[ h = racv^2 \sin^2 heta2g \] - Ready Digital AB

📅 March 7, 2026 👤 scraface

Mar 07, 2026

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2(r+1) = (3 + \sqrt{5})(r - 1)
2r + 2 = (3 + \sqrt{5})r - (3 + \sqrt{5})
2r + 2 = (3 + \sqrt{5})r - 3 - \sqrt{5}
2r - (3 + \sqrt{5})r + 2 + 3 + \sqrt{5} = 0
r = rac{5 + \sqrt{5}}{1 + \sqrt{5}}
Rationalize:
r = rac{(5 + \sqrt{5})(1 - \sqrt{5})}{(1 + \sqrt{5})(1 - \sqrt{5})} =...
Case 2:** \( rac{r+1}{r-1} = rac{3 - \sqrt{5}}{2} \)
Similarly:
2(r+1) = (3 - \sqrt{5})(r - 1)

📝 Recent Posts

A_{ ext{new}} = rac{\sqrt{3}}{4}(14)^2 = rac{\sqrt{3}}{4} \cdot 196...
\Delta A = 49\sqrt{3} - 25\sqrt{3} = 24\sqrt{3} ext{ cm}^2
Thus, the area increases by $ oxed{24\sqrt{3}} $ cmÂ².
Question: Find the length of the longest altitude of a triangle with s...
Solution: First, compute the area using Heronâs formula. Let $ a = 7...
s = rac{7 + 10 + 13}{2} = 15
The area $ A $ is:
A = \sqrt{s(s - a)(s - b)(s - c)} = \sqrt{15(15 - 7)(15 - 10)(15 - 13)...
\sqrt{1200} = \sqrt{100 \cdot 12} = 10\sqrt{12} = 10 \cdot 2\sqrt{3} =...
The altitude $ h $ corresponding to a side $ b $ is given by:

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