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\boxed\beginpmatrix 2 \\ 0 \\ -1 \endpmatrix - Ready Digital AB

📅 March 11, 2026 👤 scraface

Mar 11, 2026

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We have \( xy = 56 \) and \( x + y = 15 \).
Solving the quadratic \( t^2 - 15t + 56 = 0 \) using the quadratic for...
t = rac{15 \pm \sqrt{15^2 - 4 imes 56}}{2} = rac{15 \pm \sqrt{225 -...
The solutions are \( t = 8 \) and \( t = 7 \).
#### 7, 8
A function \( f(x) = ax^2 + bx + c \) has a vertex at \( (2, -3) \) an...
The vertex form is \( f(x) = a(x-2)^2 - 3 \).
Substitute \( (1, 0) \): \( 0 = a(1-2)^2 - 3 \).
Simplifying, \( 0 = a(1) - 3 \), so \( a = 3 \).
Expand to standard form: \( f(x) = 3(x-2)^2 - 3 = 3(x^2 - 4x + 4) - 3...

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