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Home » c(4) = (4)^2 - 3(4) + 2m = 16 - 12 + 2m = 4 + 2m - Ready Digital AB

c(4) = (4)^2 - 3(4) + 2m = 16 - 12 + 2m = 4 + 2m - Ready Digital AB

📅 March 7, 2026 👤 scraface

Mar 07, 2026

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$ (r, b, g) = (1, 1, 3) $
$ (r, b, g) = (1, 2, 2) $
$ (r, b, g) = (1, 3, 1) $
$ (r, b, g) = (2, 1, 2) $
$ (r, b, g) = (2, 2, 1) $
$ (r, b, g) = (3, 1, 1) $
Now compute the number of ways for each case using combinations:
$ \binom{8}{1} \binom{6}{1} \binom{4}{3} = 8 \cdot 6 \cdot 4 = 192 $
$ \binom{8}{1} \binom{6}{2} \binom{4}{2} = 8 \cdot 15 \cdot 6 = 720 $
$ \binom{8}{1} \binom{6}{3} \binom{4}{1} = 8 \cdot 20 \cdot 4 = 640 $

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