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📅 March 10, 2026 👤 scraface

Mar 10, 2026

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[x^2 + (y - 1)^2 + z^2] - [(x - 1)^2 + y^2 + z^2] = 0
x^2 + y^2 - 2y + 1 + z^2 - (x^2 - 2x + 1 + y^2 + z^2) = 0
-2y + 2x = 0 \quad \Rightarrow \quad x = y
Similarly, subtract (1) from (3):
[x^2 + y^2 + (z - 1)^2] - [(x - 1)^2 + y^2 + z^2] = 0
x^2 + y^2 + z^2 - 2z + 1 - (x^2 - 2x + 1 + y^2 + z^2) = 0
-2z + 2x = 0 \quad \Rightarrow \quad x = z
So $x = y = z$. Plug into equation (1):
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📝 Recent Posts

Thus, the cost of five resistors is \(\boxed{150}\).
Question:** What is the smallest prime factor of 91?
To find the smallest prime factor of 91, test divisibility by the smal...
91 is odd, so it is not divisible by 2.
Sum of digits of 91 is \(9 + 1 = 10\), which is not divisible by 3, so...
91 does not end in 0 or 5, so it is not divisible by 5.
Check divisibility by 7:
\[ 91 \div 7 = 13 \]
Since 13 is a whole number, 91 is divisible by 7. Therefore, the small...
a + b = 7 \quad \text{(1)}

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