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g(10) = 2(10) - 3 = 20 - 3 = 17 - Ready Digital AB

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Mar 07, 2026

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2x + 3\left(-\frac{32}{11}\right) = -6 \\
2x - \frac{96}{11} = -6 \\
2x = -6 + \frac{96}{11} = \frac{-66 + 96}{11} = \frac{30}{11} \\
x = \frac{15}{11}
Thus, the intersection point is $ \left( \frac{15}{11}, -\frac{32}{11}...
Final answer: $ \boxed{\left( \frac{15}{11}, -\frac{32}{11} \right)} $
Question: Factor the expression $ 16x^4 - 81y^4 $.
Recognize this as a difference of squares:
16x^4 - 81y^4 = (4x^2)^2 - (9y^2)^2 = (4x^2 - 9y^2)(4x^2 + 9y^2)
Now notice that $ 4x^2 - 9y^2 $ is also a difference of squares:

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