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Home » Is This the Most Emotional and Intense Joe conditional Walk Count Season Yet? - SITENAME

Is This the Most Emotional and Intense Joe conditional Walk Count Season Yet? - SITENAME

📅 March 7, 2026 👤 scraface

Mar 07, 2026

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📌 Subtract \(\frac{8}{3}\) from both sides:

📌 4v < 25 - \frac{8}{3} = \frac{75}{3} - \frac{8}{3} = \frac{67}{3}

📌 Now divide by 4:

📌 v < \frac{67}{12} \approx 5.583

📌 Since \( v \) is a positive integer, the largest possible value is \( v = 5 \). We verify:

📌 4(5) + \frac{8}{3} = 20 + \frac{8}{3} = \frac{68}{3} \approx 22.67 < 25

📌 Try \( v = 6 \):

📌 4(6) + \frac{8}{3} = 24 + \frac{8}{3} = \frac{72+8}{3} = \frac{80}{3} \approx 26.67 > 25

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b^2 = 625 - 49 = 576
b = \sqrt{576} = 24 \text{ cm}
Thus, the length of the other leg is:
\boxed{24 \text{ cm}}
Problem 5:
A cube has a space diagonal of \(6\sqrt{3}\) cm. What is the volume of...
The space diagonal \(d\) of a cube with side length \(s\) is given by:
d = s\sqrt{3}
d = 6\sqrt{3}
s\sqrt{3} = 6\sqrt{3} \quad \Rightarrow \quad s = 6 \text{ cm}

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