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Home » n_k = 3 + 7(k-1) = 7k - 4 - Ready Digital AB

n_k = 3 + 7(k-1) = 7k - 4 - Ready Digital AB

📅 March 7, 2026 👤 scraface

Mar 07, 2026

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📌 P = 6 \times s

📌 For the original hexagon, the perimeter is:

📌 P = 6 \times 10 = 60 \text{ cm}

📌 If each side is increased by \(2\) cm, the new side length becomes:

📌 s_{\text{new}} = 10 + 2 = 12 \text{ cm}

📌 Thus, the new perimeter is:

📌 P_{\text{new}} = 6 \times 12 = 72 \text{ cm}

📌 Expressing the new perimeter in terms of the circle’s radius \(r\), where \(r = 10\) cm, we have:

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\gcd(5^m - 1, 5^n - 1) = 5^{\gcd(m,n)} - 1.
We compute $ \gcd(24, 36) $. Using the Euclidean algorithm:
\gcd(36, 24) = \gcd(24, 12) = \gcd(12, 0) = 12.
\gcd(5^{24} - 1, 5^{36} - 1) = 5^{12} - 1.
We now compute $ 5^{12} - 1 $:
5^2 = 25, \quad 5^4 = (25)^2 = 625, \quad 5^8 = 625^2 = 390625,
5^{12} = 5^8 \cdot 5^4 = 390625 \cdot 625.
We compute $ 390625 \cdot 625 $:
Break $ 625 = 600 + 25 $, so
\cdot 600 = 390625 \cdot 6 \cdot 100 = (2,343,750) \cdot 100 = 234,375...

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