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Home » Solve for \(x\): \(2^x+1 = 32\). - Ready Digital AB

Solve for \(x\): \(2^x+1 = 32\). - Ready Digital AB

📅 March 10, 2026 👤 scraface

Mar 10, 2026

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📌 Initial proficiency: 50%

📌 Daily growth: 2% of the current proficiency

📌 We want to find \(n\) such that: \(50 \times (1.02)^n \geq 90\)

📌 Using logarithms, solve:

📌 \[ 1.02^n = \frac{90}{50} = 1.8 \]

📌 \[ n \cdot \log(1.02) = \log(1.8) \]

📌 \[ n = \frac{\log(1.8)}{\log(1.02)} \approx 29.25 \]

📌 Since \(n\) must be a whole number, round up to 30 days.

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The area of the new triangle is:
A_2 = \frac{1}{2} \times 12 \times \sqrt{133} = 6\sqrt{133} \text{ cm}...
Calculate the change in area:
\Delta A = A_2 - A_1 = 6\sqrt{133} - 60
Thus, the change in the area of the triangle is:
\boxed{6\sqrt{133} - 60 \text{ cm}^2}
Question:** A regular hexagon is inscribed in a circle of radius 10 cm...
The side length \( s \) of a regular hexagon inscribed in a circle is...
s = 10 \text{ cm}
The area \( A \) of a regular hexagon with side length \( s \) is give...

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