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Home » Then, substitute $ u = x^3 - 1 $: - Ready Digital AB

Then, substitute $ u = x^3 - 1 $: - Ready Digital AB

📅 March 11, 2026 👤 scraface

Mar 11, 2026

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3x² + 6x + 5 = 425
3x² + 6x = 420
x² + 2x = 140
x² + 2x - 140 = 0
Discriminant: \( 4 + 560 = 564 \) → not a perfect square → no integer...
Wait — maybe typo? Try correct sum.
Try x = 11: 121 + 144 + 169 = 434
x = 10: 100 + 121 + 144 = 365
x = 12: 144 + 169 + 196 = 144+169=313+196=509 → too big
No integer x gives 425?

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