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📅 March 7, 2026 👤 scraface

Mar 07, 2026

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Now, solve \( f(f(x)) = x \). This includes solutions to \( f(x) = x \...
e x \) â i.e., 2-cycles.
Letâs check the range and behavior. As \( x o \pm\infty \), \( f(x)...
Now, compute \( f(f(x)) - x = 0 \). This is a rational equation; clear...
Let \( y = f(x) \), so \( f(y) = x \). Then:
f(f(x)) = rac{(f(x))^3 - 3f(x)}{(f(x))^2 + 1} = x
Substitute \( f(x) = rac{x^3 - 3x}{x^2 + 1} \). Let \( N = x^3 - 3x \...
f(f(x)) = rac{(N/D)^3 - 3(N/D)}{(N/D)^2 + 1} = rac{ rac{N^3 - 3ND^2...
So, \( f(f(x)) = x \) becomes:
rac{N^3 - 3ND^2}{D(N^2 + D^2)} = x

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