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Home » x = 10 → width = 10 m, length = 20 m - Ready Digital AB

x = 10 → width = 10 m, length = 20 m - Ready Digital AB

📅 March 7, 2026 👤 scraface

Mar 07, 2026

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📌 Differentiate: \( f'(u) = 2(u - 1)Q(u) + (u - 1)^2 Q'(u) + a \), so \( f'(1) = a \)

📌 Compute \( f(1) \):

📌 \[ f(1) = 1^5 - 3(1)^3 + 2(1) + 8 = 1 - 3 + 2 + 8 = 8 \]

📌 \[ a + b = 8 \quad ext{(1)} \]

📌 Compute \( f'(u) \):

📌 \[ f'(u) = 5u^4 - 9u^2 + 2 \]

📌 \[ f'(1) = 5(1)^4 - 9(1)^2 + 2 = 5 - 9 + 2 = -2 \]

📌 \[ a = -2 \]

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📝 Recent Posts

= z^3 - \frac{407}{3}z - \frac{158}{3}
Diskriminante eines kubischen \( z^3 + pz + q \): \( \Delta = -4p^3 -...
Hier: \( p = -\frac{407}{3} \), \( q = -\frac{158}{3} \)
\Delta = -4\left(-\frac{407}{3}\right)^3 - 27\left(-\frac{158}{3}\righ...
Besser: positives Vorzeichen:
\( -4p^3 = -4 \cdot \left( -\frac{407^3}{27} \right) = \frac{4}{27} \c...
\( 27q^2 = 27 \cdot \frac{24964}{9} = 3 \cdot 24964 = 74892 \)
But \( p \) is large negative denominator: \( p = -\frac{407}{3} \Righ...
\( q^2 = \left(\frac{158}{3}\right)^2 = \frac{24964}{9} \), so \( 27q^...
Thus \( \Delta = 9996788 - 74892 = 9920896 > 0 \), so **three distinct...

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